Let \(\mathcal{C}\) be an arbitrary category and \(\mathcal{P}\) be a preorder thought of as a category. Are the following true?
For any two functors \(\mathcal{C}\xrightarrow{F,G}\mathcal{P}\), there is at most one natural transformation \(F \rightarrow G\)
For any two functors \(\mathcal{P}\xrightarrow{F,G}\mathcal{C}\), there is at most one natural transformation \(F \rightarrow G\)
This is true: there are no choices to be made for a natural transformation, given that for each morphism \(c\rightarrow d\) in \(\mathcal{C}\) we have to pick \(\alpha_c\) to be the morphism \(F(c)\rightarrow G(c)\) and \(\alpha_{d}\) to be the morphism \(F(d)\rightarrow G(d)\).
Counterexample:
let \(F\) send \(f\mapsto x,a\mapsto1,b\mapsto 2\) and \(G\) maps everything to \(2\)
The naturality condition for f leaves us with two choices for \(\alpha_a\)